Question

Prove that the points (-2,-1),(1,0),(4,3) and (1,2) are the vertices of parallelogram .Is it a rectangle?

Answer 1

Answer:

Step-by-step explanation:

We can prove it by distance formula as follows

A(-2,-1)B(1,0)C(4,3)D(1,2)

AB= √(x2-x1)²+(y2-y1)²

AB=√[1+(-2)]²+[(0-(-1)]²

AB=√(1²+1²)

AB=√2

BC=√(4-1)²+(3-0)²

BC=√3²+3²

BC=√9=3

CD=√(1-4)²+(2-3)²

CD√3²+1²

CD=√9+1=√10

Since Now any two of the three sides have equal ditance between obviously it is not a rectangle neither a parallelogram

If also the 4th point must be equal to one of the distances it will not make any sense

Thank you

Answer 2

Answer:

Step-by-step explanation:

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