Prove that the points (2,4), (6,4), and (6, 7) form a right angled triangle.
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distance between two points : ((x2-x1)²+(y2-y1)²)^0.5
by this formula we get distance between :1st and 2nd point distance is 4
distance between :2nd and 3rd point distance is 3
distance between :1st and 3rd point distance is 5
by pythagoras rule 3²+4² = 5²
hence distances satisfy pythagoras rule
so the points form a righ angled triangle
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