Question

prove that the points( 3 ,0), (6 ,4) and (-1 , 3) are the vertex of a right angled isosceles triangle​

Answer 1

Answer:

let A (3,0) B (6,4) and C (-1,3)

now use distance formula ,

AB=root {(6-3)^2+(4-0)^2}=root (25)=5

BC=root {(-1-6)^2+(3-4)^2}=root (50)

CA =root {((3+1)^2+(-3)^2}=5.

you see ,

BC^2 =AC^2 + AB^2

which is related to Pythagoras theorem .

hence , ABC is the vertices of right angle isoceles triangle .in which A is right angle .