Question

Prove that the points (3,-2),(4,0), 6,-3) and (5,-5) are the vertices of a parallelogram. Do it using section formula.
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Answer 1

Step-by-step explanation:

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Let the vertices of a parallelogram be A(−3,2), B(4,0), C(6,−3) and D(5,−5)

So by distance formula we have,

Distance between two points = (x2−x1)2+(y2−y1)2

AB=(4+3)2+(0+2)2=5CD=(5−6)2+(−5+3)2=5BC=(6−4)2+(−3)2=13AD=(5−3)2+(−5+2)2=13

Opposite site of a parallelogram are equal.

Therefore AB=CD=5 and BC=AD=13

ABCD is a parallelogram (PROVED)