Prove that the points (3, 2), (6, 3), (7, 6), (4, 5) are the vertices of a parallelogram. Is it a rectangle?
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Answer:
In a parallelogram the diagonals are equal.
If the mid points are equal then it's
parallelogram
Step by step explanation:
let the given points be a,b,c,d respectively
Formula for finding mid point:
{x1+x2÷2,y1+y2÷2}
(3+7÷2,2+6÷2). | (6+4÷2,3+5÷2)
|
(10÷2,8÷2). | ( 10÷2,8÷2)
|
(5,4) | (5,4)
Here the mid points r equal .
Therefore the quadrilateral formed is parallelogram .Hence it is not rectangle.
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