Question

prove that the points (3a,0);(0,3b)and (a,2b)are colliner
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Answer 1

To prove points are collinear

We use formula of Area of triangle by point.

If Area of triangle equals to 0 then points are collinear.

Area of triangle is given by,

Area of Triangle = 1/2(x1(y2−y3)+x2(y3−y1)+x3(y1−y2))

Area of Triangle= 1/2 (3a( 3b - 2b ) + 0( 2b - 0) + a( 0 - 3b) )

Area of Triangle = 1/2( 3ab - 3ab )

Area of Triangle = 0

Therefore, Given Points are collinear

Hence this points form straight line.