Prove that the points (4, 5) (7, 6) (4, 3) (1, 2) are the vertices of a parallelogram.
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Answer:
ABCD is a Parallelogram
Step-by-step explanation:
parallel lines have same slopes
let A(4,5) B(7,6) C(4,3) and D(1,2)
Slope of AB = 6-5 / 7-4 = 1/3
Slope of CD = 3-2 / 4-1 = 1/3
therefore, AB||CD
Slope of AD = 5-2 / 4-1 = 3/3 = 1
Slope of BC = 6-3/7-4 = 3/3 = 1
therefore, AD||BC
Opposite sides are parallel to each other.
Hence, ABCD is a parallelogram.
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