Question

prove that the points (7, 10) (-2, 5) and (3, -4) are the vetices of an isoceles right triangle​

Answer 1

Answer:

the points (7, 10) (-2, 5) and (3, -4) are the vetices of an isoceles right triangle

(7, 10), (-2, 5) =

$\sqrt{81 + 25} = \sqrt{106}$

(7, 10) (3, -4) =

$\sqrt{16 + 196} = \sqrt{212}$

(-2, 5) and (3, -4) =

$\sqrt{25 + 81} = \sqrt{106}$

Two sides are equal so this is isosceles triangle

And also square of hypotenuse = square of base + square of altitude.

212 = 106 + 106

So,

This is right isosceles triangle.