prove that the points (-7,-3),(5,10),(15,8), and (3,-5) taken in order are the corners of the rhombus and find its area
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Prove that the points ( - 7...
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Asked on December 26, 2019 byPandi Rawat
Prove that the points (−7,−3),(5,10),(15,8) and (3,−5) taken in order are the corners of a parallelogram.
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Let A, B, C and D represent the points (-7, -3), (5, 10), (15, 8) and (3, -5) respectively.
Using the distance formula d=(x2−x1)2+(y2−y1)2, we find
AB2=(5+7)2+(10+3)2=122+132=144+169=313
BC2=(15−5)2+(8−10)2=102+(−2)2=100+4=104
CD2=(3−15)2+(−5,−8)2=(−12)2+(−13)2=
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