Prove that the points (−7, −3), (5, 10), (15, 8) and (3, −5) taken in order are the corners and find its area
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let A=(-7,-3)
B=(5,10)
C=(15,8)
D=(3,-5)
dist.b/w AB = ([-7-5]^2 + [-3-10]^2) ^1/2
= (144 + 169)^1/2
= (313)^1/2 = 17.69
dist.b/w BC = ([5-15]^2 + [10-8]^2)^1/2
= (100 + 4)^1/2
= (104)^1/2 = 10.19
dist.b/w CD = ([15-3]^2[8+5]^2)^1/2
= (144 + 169)^1/2
=(313)^1/2 = 17.69
dist.b/w AD = ([-7-3]^2[-3+5]^2)^1/2
= (100 + 4 )^1/2
= (104)^1/2 = 10.19
=>
opp. sides are equal in the fig.
area = l * b
= 17.69*10.16
= 180.26 sq.units
B=(5,10)
C=(15,8)
D=(3,-5)
dist.b/w AB = ([-7-5]^2 + [-3-10]^2) ^1/2
= (144 + 169)^1/2
= (313)^1/2 = 17.69
dist.b/w BC = ([5-15]^2 + [10-8]^2)^1/2
= (100 + 4)^1/2
= (104)^1/2 = 10.19
dist.b/w CD = ([15-3]^2[8+5]^2)^1/2
= (144 + 169)^1/2
=(313)^1/2 = 17.69
dist.b/w AD = ([-7-3]^2[-3+5]^2)^1/2
= (100 + 4 )^1/2
= (104)^1/2 = 10.19
=>
opp. sides are equal in the fig.
area = l * b
= 17.69*10.16
= 180.26 sq.units
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