Prove that the points (−7, −3), (5, 10), (15, 8) and (3, −5) taken in order are the corners
of a parallelogram.
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A(-7,-3) B(5,10) C(15,8) D(3,-5)
Slopes of AB = 13/12 AD = -2/10 =-1/5 BC = -2/10 = -1/5
CD = -13/-12 = 13/12
AB || CD AD || BC
hence ABCD is a parallelogram
Slopes of AB = 13/12 AD = -2/10 =-1/5 BC = -2/10 = -1/5
CD = -13/-12 = 13/12
AB || CD AD || BC
hence ABCD is a parallelogram
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