Prove that the points A(1,1) , B(-2,7) and C(3,-3) are collinear.
Answers
Answered by
12
its me NISHANT MISHRA!!
SOLUTION:
for collinear
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0
HERE,
x1=1 ,y1=1
x2=-2, y2=7
x3=3, y3=-3
1(7+3)-2(-3-1)+3(1-7)=0
10+8-18=0
0=0
it is collinear!!
SOLUTION:
for collinear
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0
HERE,
x1=1 ,y1=1
x2=-2, y2=7
x3=3, y3=-3
1(7+3)-2(-3-1)+3(1-7)=0
10+8-18=0
0=0
it is collinear!!
NishantShandilya:
hope it help
plz mark as brianliest
apki (y1 - y2) ki value galat h bro..
shi hai
Answered by
6
A(1,1), B(-2,7) C(3,-3)
By using Area of triangle formula ==》
=1/2 [ x1 ( y2 - y3 ) + x2 (y3- y1) + x3 (y1 - y2) ]
=1/2{ [1 (7-(-3)] + (-2)(-3-1) + 3(1-7) }
=1/2 ( 10 + 8 - 18)
=1/2 ( 0)
=0
So that they are collinear ....
HOPE ITS help you....
thnks ....;))
By using Area of triangle formula ==》
=1/2 [ x1 ( y2 - y3 ) + x2 (y3- y1) + x3 (y1 - y2) ]
=1/2{ [1 (7-(-3)] + (-2)(-3-1) + 3(1-7) }
=1/2 ( 10 + 8 - 18)
=1/2 ( 0)
=0
So that they are collinear ....
HOPE ITS help you....
thnks ....;))
shi hai
okk...to bhi answer 0 hai....
acha jao kon smjhaye
bhai ap apne answer mai y1 - y2 ki value thik karlo .....wo galat hai......is wajah se apka answer wrong h
shi hai
good
hmm
ab sahi h...
dont say bro
i m not ur bro
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