prove that the prependicular at point of contact to tangent to a circle passes the centre
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o is the centere of given circle
a tangent PR is drawen touching by the circle of point P.
draw QP parllel to RP at point P such that point Q lies on the circle
angle QPR = 90 degree ( radius parllel tangent)
also angle QPR = 90 degree
therefore, angle QPR = angle QRP
now, above case is possible only when the centrel o lies on the line QP
hence perpendicular at the the point of contact o the tangent to the circle passes through the centralof circle
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