Math, asked by famidabegum, 1 year ago

prove that the product of 2 odd natural numbers is odd

Answers

Answered by saanviy01
14

Answer:


Step-by-step explanation:

Let a and b be two odd numbers....

If a and b are odd, then a and b can be written as:

a=2m+1 ,

b=2n+1

Where m and n are whole numbers.

So....

ab=(2m+1)(2n+1)

=4mn+2m+2n+1

=2(2mn+m+n)+1

Which is odd.

Bcz it leaves the remainder 1 after being divided by 2....

Hope it helps....:-)


famidabegum: i have mentioned in the question as "natural"
saanviy01: The solution is right but if u exactly want to mention natural number there so on the very first line of the solution you can write "let a and b be two odd natural numbers" but there is no change in the procedure...
saanviy01: And while taking m and n u can mention the word natural... I hope it is clear..
rk5948411: OK, u r right
famidabegum: thanks
saanviy01: Thanks u too
Answered by rk5948411
1

Answer:


Step-by-step explanation:

Consider the sum a + b = (2n + 1) + (2m +1) = 2n + 2m +2 = 2k, where k = n + m + 1 is an integer. Therefore by definition of even we have shown that a + b is even and my hypothesis is true. 5) The product of two odd integers is odd. Proof: Let n and m be two odd integers.

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