prove that the product of 2 odd natural numbers is odd
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Answered by
14
Answer:
Step-by-step explanation:
Let a and b be two odd numbers....
If a and b are odd, then a and b can be written as:
a=2m+1 ,
b=2n+1
Where m and n are whole numbers.
So....
ab=(2m+1)(2n+1)
=4mn+2m+2n+1
=2(2mn+m+n)+1
Which is odd.
Bcz it leaves the remainder 1 after being divided by 2....
Hope it helps....:-)
famidabegum:
i have mentioned in the question as "natural"
Answered by
1
Answer:
Step-by-step explanation:
Consider the sum a + b = (2n + 1) + (2m +1) = 2n + 2m +2 = 2k, where k = n + m + 1 is an integer. Therefore by definition of even we have shown that a + b is even and my hypothesis is true. 5) The product of two odd integers is odd. Proof: Let n and m be two odd integers.
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