Question

prove that the product of any 3 consecutive positive integers is divided by 6.​

Answer 1

lets take 3 consecutive number

n

n+1

n+2

product of them

= n × n+1 × n+2

= ( n^2+n ) × ( n+2 )

= n^3 + 3n^2 + 2n

now put 1,2,3...n

and we will get

6,24,60....

this can be devied by 6.

hope you understand

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