prove that the product of any two consecutive even natural is divisible by 4
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Step-by-step explanation:
LET US TAKE TWO NUMBERS : 2n,2n+2
here i have taken 2n and 2n+2 because they are even consecutive natural numbers.The difference between these numbers should always be 2.
now lets multiply these numbers- (2n)(2n+2)= 4n^2+4n =4(n^2+n).
4(n^2+n) is always divisible by 4.
hence proved.
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