Prove that the product of three consecutive integers is divisible by 6
Answers
Answered by
1
x.y.z = 6
x.x+1.x+2 = 6
3x +3 = 6
3x =6-3
3x =3
x=3/3
x=1
y =2
z=3
x.x+1.x+2 = 6
3x +3 = 6
3x =6-3
3x =3
x=3/3
x=1
y =2
z=3
Similar questions