Question

prove that the product of three consecutive natural numbers is divisible by 6

Answer 1

Prove that the product of three consecutive natural numbers is divisible by 6

let one number be n

then other 2

n +1 and n +2

now 

let n  be 2

so 

n *n+1 *n+2 =  2 *2+1*2+2

=> 2 * 3*4

=> 24

24  is divisible by 6

hence  product of three consecutive natural numbers is divisible by 6

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