prove that the product of three consecutive positive integers is divisible by 6.
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Answered by
3
Let the integers be n, n+1,n+2
Let n=1
=n×(n+1)×(n+2)
=1×(1+1)×(1+2)
=1×2×3
=6
It is divisible by 6
U can verify this using any value for n... answer will be divisible by 6
Let n=1
=n×(n+1)×(n+2)
=1×(1+1)×(1+2)
=1×2×3
=6
It is divisible by 6
U can verify this using any value for n... answer will be divisible by 6
Answered by
1
Hi,
Here is your answer
Let the three positive consecutive integers are 1, 2, 3.
The product of these numbers = 1*2*3 = 6
6 is divisible by 6 ⇒ 6/6 = 1
Hence it is proved.
Hope it helps you.
Here is your answer
Let the three positive consecutive integers are 1, 2, 3.
The product of these numbers = 1*2*3 = 6
6 is divisible by 6 ⇒ 6/6 = 1
Hence it is proved.
Hope it helps you.
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