prove that the product of three consecutive positive integer is divisible by 6.
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1×2×3=6
2×3×4=24
3×4×5=60
4×5×6=120
In every 3 consecutive numbers there is a number which is divisible by 3 and 2 so 3 × 2 = 6.So the product of every 3 consecutive number is divisible by 6.
2×3×4=24
3×4×5=60
4×5×6=120
In every 3 consecutive numbers there is a number which is divisible by 3 and 2 so 3 × 2 = 6.So the product of every 3 consecutive number is divisible by 6.
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Answer:
when a number is divided by 3, the remainder obtained is 0 or 1 or 2. so, we can say that one of the numbers n, n + 1 and n + 2 is always divisible by 3. n (n + 1) (n + 2) is divisible by 3. ... n (n + 1) (n + 2) is divisible by 6.
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