Prove that the product of three consecutive positive integer is divisible by 6.
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for n, n+1 and n+2,
since they are consecutive, one of them must be divisible by 3 and at least one must be divisible by 2
so when you multiply the total must be divisible by both 2 and 3 therefore must be divisible by 6
since they are consecutive, one of them must be divisible by 3 and at least one must be divisible by 2
so when you multiply the total must be divisible by both 2 and 3 therefore must be divisible by 6
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