Question

prove that the product of two consecutive even integer is divisible by 8​

Answer 1

Let the first number be 2n (since it is even), and the next number be 2n+2

The product is (2n)(2n+2)=(2)(n)(2)(n+1)

And that is 4n(n+1)

Now. If n is odd, n+1 is even. Let n+1=2k

We have 4n(2k)=8k which is divisible by 8.

If n is even, let n=2k

We have 4(2k)(n+1)=8k , which is divisible by 8.

I hope this will be help ful to you

Answer 2

Ans

Step-by-step explanation:

Consecutive means ek ke baad ek you know.