prove that the product of two consecutive integers is divisible by 2
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Answered by
121
Answer:
Let the 2 consecutive numbers be, x,x+1
product of these consecutive numbers, =x(x+1)
(1) even
let, x=2k
product =2k[2k+1]
from above equation it is clear that the product is divisible by 2
(2) odd
let, x=2k+1
product =(2k+1)[(2k+1)+1]
=2(2k² +3k+1)
from above equation it is clear that the product is divisible by 2
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Answered by
1
Let we take the integers be 5&6
product=6*5=30
And 30 is divisible by 2
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