prove that the product of two consecutive positive integers is divisible by 2
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Answered by
2
Answer:
the two consecutive is divisible by 2
therefore positive integer are consecutive of 2 which is divisible by two consecutive
Step-by-step explanation:
thank you
I don't know the answer
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Answered by
0
Step-by-step explanation:
Let the 2 consecutive numbers be, x,x+1
product of these consecutive numbers, =x(x+1)
(1) even
let, x=2k
product =2k[2k+1]
from above equation it is clear that the product is divisible by 2
(2) odd
let, x=2k+1
product =(2k+1)[(2k+1)+1]
=2(2k2+3k+1)
from above equation it is clear that the product is divisible by 2
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