Question

prove that the product of two odd natural number is odd​

Answer 1

SOLUTION

For any Integer to be odd, it is not exactly divisible le by 2 and it can be described by the formula “ 2n + 1 “ where “ n “ is any integer.

Let us therefore consider two odd integers, being ( 2n + 1 ) and ( 2n + 3 ).

In this case, the two numbers are both odd and are consecutive.

That the two numbers are consecutive is irrelevant to this question.

That they are both odd is the important fact.

Their product is ( 2n + 1 ) * ( 2n + 3 ) or

4n² + 6n + 2n + 3 or

4n² + 8n + 3 or

4n( n + 2) + 3

By definition 4n is even because 4n = 2 * 2n and both “ 2 “ and therefore “ 2n “ are even..

However “ 3 “ is odd, so [ 4n(n + 2) + 3 ] is odd.

Therefore the product of these two odd integers is odd.

Hope you understand it

Thank you

Answer 2

Step-by-step explanation:

I hope it will be help full for you