Question

prove that the quadilateral formed by the internal angle bisector of any quadilateral is cyclic

Answer 1

Given :- A quadrilateral ABCD with internal angle bisectors AF, BH, CH
and DF of angles A, B, C and D respectively and the points E, F, G
and H form a quadrilateral EFGH.

To prove :- EFGH is a cyclic quadrilateral.

∠HEF = ∠AEB [Vertically opposite angles] -------- (1)
Consider triangle AEB,
∠AEB + ½ ∠A + ½ ∠ B = 180°
∠AEB  = 180° – ½ (∠A + ∠ B) -------- (2)

From (1) and (2),
∠HEF = 180° – ½ (∠A + ∠ B) --------- (3)

Similarly, ∠HGF = 180° – ½ (∠C + ∠ D) -------- (4)

From (3) and (4),
∠HEF + ∠HGF = 360° – ½ (∠A + ∠B + ∠C + ∠ D)
                          = 360° – ½ (360°)
                          = 360° – 180°
                          = 180°
So, EFGH is a cyclic quadrilateral since the sum of the opposite
angles of the quadrilateral is 180°.