Question

prove that the quadratic equation x^2+9x-4=0 has distunct real root​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

${x}^{2} + 9x - 4 \\ a = 1 \: b = 9 \: c = - 4 \\ {b}^{2} - 4ac \\ {9}^{2} - 4 \times 1 \times - 4 \\ 81 + 16 \\ 97$

therefore roots are real roots