Question

prove that the quadratic equation x^2 + ax - 4 =0 has distinct, real roots
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Answer 1

Answer:

For know the value of roots are distinct , We have to calculate discriminate ..

D= b^2 − 4ac

Here, ftom question..

x^2 + ax - 4 =0

a=1 , b=a , C= -4

D = a^2− 4×1×(-4)

= a^2+16

a^2 is always positive.

So, the value of 'D'positive this we can say that quadratic equation has two real and distinct root.