Question

Prove that the quadratic equation
x²+ax-4=0 has distict, real roots.​

Answer 1

Answer:

it can be solved throught splitting the middle term

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given, Quadratic equation-

x^2+ ax-4=0

on comparing with general form of quadratic equation-- ax^2+bx^2+c=0

Here,a= 1,b= a,c= -4

Now, Discriminant,D » 0

b^2-4ac » 0

a^2 - 4×1×(-4) » 0

a^2 + 16 » 0

Here, It's clear that a^2+16 is greater than 0

so,the equation has distinct and real root's

Hence, proved