Math, asked by pimplevaibhavi1, 2 months ago

prove that the quadrilateral formed by bisector of all interior angle of a rhombus is rectangle​

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Answered by mauryasangita716
1

Answer:

prove that the quadrilateral formed by bisector of all interior angle of a rhombus is rectangle

Step-by-step explanation:

Given Let ABCD be a parallelogram and AP, BR, CR, be are the bisectors of ∠A, ∠B, ∠C and ∠D, respectively. To prove Quadrilateral PQRS is a rectangle. ... Thus, PQRS is a quadrilateral whose each angle is 90°. Hence, PQRS is a rectangle.

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