prove that the quadrilateral formed by bisector of all interior angle of a rhombus is rectangle
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prove that the quadrilateral formed by bisector of all interior angle of a rhombus is rectangle
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Given Let ABCD be a parallelogram and AP, BR, CR, be are the bisectors of ∠A, ∠B, ∠C and ∠D, respectively. To prove Quadrilateral PQRS is a rectangle. ... Thus, PQRS is a quadrilateral whose each angle is 90°. Hence, PQRS is a rectangle.
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