Question

Prove that the quadrilateral formed by internal angle bisectors of a parallelogram is a rectangle with the help of proper sketch.
Explain with pen on paper.

Give correct explanation and I'll mark you the BRAINLIEST!!!​

Answer 1

Answer:

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Step-by-step explanation:

Refer image

Given : ABCD a parallelogram

To Prove : PQRS is a rectangle  

DC∣∣AB and DA is a traversal  

∴∠A+∠D=180  

0

 

2

1

​  

∠A+  

2

1

​  

∠D=90  

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⇒∠SAD+∠SDA=90  

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∴∠ASD=90  

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∴ By concept of vertical angles

∠ASD=∠PSR=90  

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Simillarly we will get

∠PQR=∠QPS=∠QRS=90  

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∴PQRS is a rectangle