Prove that the quadrilateral formed by joining the midpoints of consecutive sides of rectangle is a rhombus and PLEASE PROVE THE VICE-VERSA ALSO.
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Abcd is parallelogram
Mid point p q r s
Its a rectangle tough
So ab bd ca ad are equal sides and thus all are equal as 1 = 2 and 2 = 3 . Thus 1= 3 .
Hence its a rhombud
Mid point p q r s
Its a rectangle tough
So ab bd ca ad are equal sides and thus all are equal as 1 = 2 and 2 = 3 . Thus 1= 3 .
Hence its a rhombud
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