Question

prove that the qudrilateral formed by the bisectors of a ||gm is a rectangle.​

Answer 1

Note : U haven't mentioned any diagram , so each points I have assumed ...

Let ABCD be a parallelogram and AP, BR, CR, be are the bisectors of ∠A, ∠B, ∠C and ∠D, respectively.

To prove Quadrilateral PQRS is a rectangle.

Proof Since, ABCD is a parallelogram, then DC || AB and DA is a transversal.

∠A+∠D= 180°

[sum of cointerior angles of a parallelogram is 180°]

⇒ 1/2 ∠A+ 1/2 ∠D = 90° [dividing both sides by 2]

∠PAD + ∠PDA = 90°

∠APD = 90° [since,sum of all angles of a triangle is 180°]

∴ ∠SPQ = 90° [vertically opposite angles]

∠PQR = 90°

∠QRS = 90°

and ∠PSR = 90°

Thus, PQRS is a quadrilateral whose each angle is 90°.

Hence, PQRS is a rectangle.

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