prove that the radius of curvature at any point (x, y) for
![\sqrt[3]{x} + \sqrt[3]{y} = \sqrt[3]{a}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7Bx%7D++%2B++%5Csqrt%5B3%5D%7By%7D++%3D++%5Csqrt%5B3%5D%7Ba%7D+ "\sqrt[3]{x} + \sqrt[3]{y} = \sqrt[3]{a}")
is 3(axy)^1/3
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Total no of balls is 3+5+7=15 Favorable cases (not black) =10(3+7) P(not black) = favourable outcomes /total no of outcomes So here P(not black) =10/15=2/3 Therefore the probability that the ball drawn is not black is 2/3 Pls mark as brainliest..
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