Question

Prove that the ratio of perimeter of 2 similar triangle
is the same as the ratio of their corresponding sides.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let the two similar △les be △ABC&△PQR.

When△les are similar,

1.The corresponding angles are equal.

2.The ircorresponding sides are proportional.

hence in △ABC&△PQR

PQAB=QRBC=PRAC

The perimeter of △ABC=AB+BC+AC−(i)

The perimeter of△PQR=PQ+QR+PR−(ii)

∴PQAB=QRBC=PRAC=PQ+QR+PRAB+BC+AC

=Perimeterof△PQRPerimeterof△ABC

If I'm correct please mark me as brilliant......