PROVE THAT THE RATIO OF THE AREA OF TWO SIMILAR TRIANGLES IS EQUAL TO THE RATIIO OF THE SQUARES OF THEIR CORRESPONDING SIDES
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Here it is!Sorry about the handwriting.
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sorry for saying this but that answer is wrong , but almost corret and we want prove area of "abc"/ = (ab/pq)square =(bc/qr)square=(am/pn)square
area of "pqr"
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