Question

Prove that the ratio of the areas of similar triangles is equal to the ratio of the squares on the corresponding sides.Using above result,find the ratio of the areas of Triangle ADC and Triangle ABC when ABC is a right angled triangle at A with AD perpendicular to BC,BC=12cm and AC=5cm

Answer 1

Answer:

Step-by-step explanation:

Also area of abc and adc

We have

Ar adc /ar abc =12 ×12/5×5=144/25

For proving it similar we have d and a=90 and c is common

Hence they r congrant by AA