Question

Prove that the ratio of the areas of two similar triangle is equal to the square of the ratio corresponding circum radius

Answer 1

Step-by-step explanation:

ANSWER

Given:△ABC∼△PQR

To prove:ar(△PQR)ar(△ABC)=(PQAB)2=(QRBC)2=(PRAC)2

Construction:Draw AM⊥BC and PN⊥QR

Proof:area(△ABC)=21×base×height=21×BC×AM         ........(1)

area(△PQR)=21×base×height=21×QR×PN         ........(2)

Dividing (1) by (2) we get

ar(△PQR)ar(△ABC)=21×QR×PN21×BC

Answer 2

Answer:

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Step-by-step explanation:

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