Question

Prove that "the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides

Answer 1

Next steps are :

Area of triangle = 1/2 base × height

Area of ∆ABC. 1/2 BC × AL
----------------------- =. -------------------
Area of ∆PQR. 1/2 QR × PN

= BC. × AL
-- -----. ------
QR. PN

=BC/QR × AL/PN

=BC/QR × Bc/QR

=(BC)^2/(QR)^2

similarly all sides become in this ratio

HOPE IT HELPS YOU...

Answer 2

$\textbf{Answer is in Attachment !}$