Prove that the ratio of the peremeters of two similar triangles is the same as the ratio of their corresponding sides
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hlo frnd hope this hlps u..
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HERE IS YOUR ANSWER
Let the sides of one triangle be a, b, c and other triangle be d, e, f
Thus according to question
Sides of similar traingle are equal
thus
a = d
b = e
and
c = f
Thus
perimeter of triangle = a + b + c = d + e + f
Thus
ratio of perimeters = 1 : 1
and
sides = a/d =b/e = c/f = 1
HOPE THIS HELPS...
Let the sides of one triangle be a, b, c and other triangle be d, e, f
Thus according to question
Sides of similar traingle are equal
thus
a = d
b = e
and
c = f
Thus
perimeter of triangle = a + b + c = d + e + f
Thus
ratio of perimeters = 1 : 1
and
sides = a/d =b/e = c/f = 1
HOPE THIS HELPS...
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