Question

Prove that the ratio of the perimeter of two similar triangle is the same as the ratio of their corresponding sides

Answer 1

Step-by-step explanation:

let the 2 similar triangles be ABC and PQR

sides of ∆ABC are AB BC AC

sides of ∆PQR are PQ QR PR

the ratio of the two similar triangles are

AB/PQ = BC/QR = AC/PR

Perimeter of ∆ABC = AB+BC+AC (equ 1)

Perimeter of ∆PQR = PQ+QR+PR (equ 2)

divide the equ 1 by equ 2 we get

$= \frac{ab + bc + ac}{pq + qr + pr}$