Question

Prove that the ratio of the size of similar triangles is equal to the ratio of the perimeter

Answer 1

a/a2=k

b/b2=k

c/c2=k. (A/C , similarity)

then

P/p1=a+b+c/a2k+b2k+c2k

= a+b+c/k(a2+b2+c2)

or,

a+b+c/a2+b2+c2=k. (Ratio of crossponding side)