Prove that the rectangle which circumscribed a circle is a square
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Answer:
Step-by-step explanation:
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In the provided figure the marking are done by the rule that 'the two tangents drawn to a circle from a fixed point has same length'
As the quadrilateral is a rectangle
a+d=b+c
∴ a=b+c-d-----------------------------------(1)
From the above reason
a+b=c+d
from (1)
b+c-d+b=c+d
⇒ 2b=2d
⇒ b=d-----------------------------------------(2)
Substituting from (2) in (1)
a+d=c+d
⇒ a=c------------------------------------------(3)
From (2) and (3)
a+d = a+b-----------------------------------(4)
Similarly we can prove that
a+b=b+c-----------------------------------(5)
and b+c=c+d------------------------------------(6)
and c+d=a+d------------------------------------(7)
From (4) , (5) , (6) and (7) we can prove that the rectangle is a square.