Prove that the relation r on the set a ={1,2,3,4,5} given by r
Answers
Answered by
0
Given the set A={1,2,,3,4,5} and the relation R={(a,b):|a−b|iseven}:
Let a=b, (a,a)∈R→|a−a|=0 which is even. Therefore R is reflexive.
For R to be symmetric, if (a,b)∈R→(b,a)∈R.
(a,b)∈R→|a−b|=even
(b,a)∈R→|b−a|=even
(a−b)=−(b−a); therefore |(a−b)|=|(b−a)|
Therefore (b,a)∈R. Hence, R is symmetric
Let (a,b)∈Rand(b,c)∈R
⇒|a−b|iseven and |b−c|iseven
If (a,c)∈R→|a−c|=even
Now, a−c=a−b+b−c, which is an even number, as the sum of even numbers is even.
Hence R is transitive.
Since R is reflexive, symmetric and transitive. R is an eqivalence relation.
Similar questions