Question

Prove that the rhombus circumscribing a circle is a square​

Answer 1

Answer:

According to the tangent property

AQ=AP

Similarly BQ=BR, RC=CS, DC=PD

Therefore aq+qb=br+rc=ds+sc=ap+pd

All sides are equal

Radius and the tangent are perpendicular to each other

So it is a square ⬜