Question

prove that the right bisector of a chord bisects the corresponding minor arc of the circle.

Answer 1

This can be done by proving that angle AOL =angle BOL
which is possible by proving the congruency of Triangle AOL and Triangle BOL

Answer 2

hay!!

dear user-

Let AB be a chord of a circle C(o,r)

Let PQ be right bisector of chord AB intersecting it at L and the circle of P and Q

Since, the right bisector of a chord always passes through the center of the circle, PQ must pass through O.

join OA and OB.

in △OLA and △OLB, we have :

OA=OB. [each equal to R]
ㄥALO=ㄥBOL
OL=OL
△OLA≈△OLB
ㄥAOL=ㄥBOL
ㄥAOP=ㄥBOP

m(AP)=m(BP)

AP≈BP

I hope it's help you