Question

Prove that the roots of the equation 2(a²+b²)x²+2(ab+b)x+1=0 are complex.

Answer 1

Here,
the given Quadratic equation is 2(a²+b²)x²+2(ab+b)x+1=0.

where
A=2(A²+B²)
B=2(ab+b)
C=1.

Discriminant of this equation is
D=B2-4AC
=[2(ab+b)]^2- 4.2(A²+B²).1
=4a2b2+4b2+8ab2-8a2-8b2
Hence, roots of this equation is complex.
OR.
roots cannot be find out.