Prove that the segment joining the points of contact of two parallel tangents passes through center
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Step-by-step explanation:
Consider AB and CD are two parallel tangents to the circle.
Consider P and Q be the point of contact and POQ be a line segment.
Construction: Join OP and OQ where O is the centre of a circle.
Proof: OQ ⊥CD and OP ⊥ AB.
Since AB || CD, OP || OQ.
As OP and OQ pass through O,
Hence, POQ is a straight line which passes through the centre of a circle
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