Prove that the set g = (1, 2, 3, 4, 5, 6) is an abelian group under multiplication modulo 7.
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Answer:
see below
Step-by-step explanation:
a × b = c (mod 7)....(1)
a × b = b × a = c
hence....
b × a = c (mod 7).....(2)
from (1), (2)....
a × b = b × a = (mod 7)
therefore g is abelian
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