prove that the square of an odd integer decreased by 1 is a multiple of 8
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1
Answer:
follow the attachment given above..you can even take 2x +1 but multiple will be in fraction...
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5
Answer:
hey mate here is your answer....
Step-by-step explanation:
➡️ Let a = 4k + 1 or 4k + 3
➡️ a² = 16k² + 8k + 1 or a² = 16k² + 24k + 9
➡️ a² - 1 = 8k(2k + 1) or a² - 1 = 8 ( 2k² + 3k + 1)
▶️ a² - 1 is a multiple of 8.
☑️ Thus when 1 subtracted from square of an odd integer then the integer so obtained is multiple of 8.
Hope it helps!☺️
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