Question

prove that the square of an odd integer decreased by 1 is a multiple of 8​

Answer 1

Answer:

follow the attachment given above..you can even take 2x +1 but multiple will be in fraction...

Answer 2

Answer:

hey mate here is your answer....

Step-by-step explanation:

➡️ Let a = 4k + 1 or 4k + 3

➡️ a² = 16k² + 8k + 1 or a² = 16k² + 24k + 9

➡️ a² - 1 = 8k(2k + 1) or a² - 1 = 8 ( 2k² + 3k + 1)

▶️ a² - 1 is a multiple of 8.

☑️ Thus when 1 subtracted from square of an odd integer then the integer so obtained is multiple of 8.

Hope it helps!☺️